According to Ohm's Law, if the applied voltage doubles while resistance stays the same, how does current change?

According to Ohm's Law, if the applied voltage doubles while resistance stays the same, how does current change?

• A. It stays the same
• B. It quadruples
• C. It doubles
• D. It halves

Answer: (C)

Current is proportional to voltage when resistance is constant, because I = V / R. If the resistance doesn’t change and the voltage doubles, the current doubles as well: I2 = (2V) / R = 2(V / R) = 2I. So doubling the voltage pushes twice as many coulombs per second through the same resistance. For example, with 10 V across 5 Ω, current is 2 A; with 20 V across the same 5 Ω, current is 4 A. The other options would require either no change in current or a different relationship, which would need a change in voltage or resistance.

Current is proportional to voltage when resistance is constant, because I = V / R. If the resistance doesn’t change and the voltage doubles, the current doubles as well: I2 = (2V) / R = 2(V / R) = 2I. So doubling the voltage pushes twice as many coulombs per second through the same resistance. For example, with 10 V across 5 Ω, current is 2 A; with 20 V across the same 5 Ω, current is 4 A. The other options would require either no change in current or a different relationship, which would need a change in voltage or resistance.